Solved] find sin (alpha-beta) cos alpha = 5/13, alpha in quadrant I sin beta = -5/13, beta in quadrant III | Course Hero
![Page 362 Qtn 3 Find out the distance between the following pairs of points a cos alpha a sin alpha and a cos beta a sin beta a m1 2 2 am1 Page 362 Qtn 3 Find out the distance between the following pairs of points a cos alpha a sin alpha and a cos beta a sin beta a m1 2 2 am1](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=2fdb49ef442ca945c150d2e60334f44c.png&d=0)
Page 362 Qtn 3 Find out the distance between the following pairs of points a cos alpha a sin alpha and a cos beta a sin beta a m1 2 2 am1
![sin alpha sin beta m and cos alpha cos beta n find tan alpha beta 2 - Mathematics - TopperLearning.com | wlcziqq sin alpha sin beta m and cos alpha cos beta n find tan alpha beta 2 - Mathematics - TopperLearning.com | wlcziqq](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=9de0e08e81655f376d5be4fcdfc52dce.png)
sin alpha sin beta m and cos alpha cos beta n find tan alpha beta 2 - Mathematics - TopperLearning.com | wlcziqq
Given that sin alpha is 1/3 and tan beta is -3/4, lying on the 2nd and 4th quadrants, respectively, how do I solve for sin(a+b)= (sin a×cos b) + (cos a×sin b)? -
![SOLVED:Find (a) \sin \alpha and \cos \beta,(b) \tan \alpha and \cot \beta, and (c) \sec \alpha and \csc \beta. Graph cannot copy SOLVED:Find (a) \sin \alpha and \cos \beta,(b) \tan \alpha and \cot \beta, and (c) \sec \alpha and \csc \beta. Graph cannot copy](https://cdn.numerade.com/previews/62e12d57-0a27-4973-954d-39b8e93e2798.gif)
SOLVED:Find (a) \sin \alpha and \cos \beta,(b) \tan \alpha and \cot \beta, and (c) \sec \alpha and \csc \beta. Graph cannot copy
7, If cos (theta +iphi )=cos alpha +isin alpha , prove that(i) sin alpha =pm sin ^{2}theta (ii) sin alpha =pm sin h^{2} phi | Snapsolve
![Prove that dfrac{sin alpha +sin beta}{sinalpha -sinbeta}=dfrac{tan dfrac{ alpha +beta}{2}}{tandfrac{alpha -beta}{2}}. Prove that dfrac{sin alpha +sin beta}{sinalpha -sinbeta}=dfrac{tan dfrac{ alpha +beta}{2}}{tandfrac{alpha -beta}{2}}.](https://media-ez.b-cdn.net/storage/questions/2020-08-16/1556027_1729848_ans_3fa22f573a98433aa402386217820239.jpg)
Prove that dfrac{sin alpha +sin beta}{sinalpha -sinbeta}=dfrac{tan dfrac{ alpha +beta}{2}}{tandfrac{alpha -beta}{2}}.
![If A ( cos alpha , sin alpha) B(sin alpha , - cos alpha ) C(1,2) are the vertices of a triangle ABC then as alpha varies, the locus of its centroid is If A ( cos alpha , sin alpha) B(sin alpha , - cos alpha ) C(1,2) are the vertices of a triangle ABC then as alpha varies, the locus of its centroid is](https://embibe-ask.s3.amazonaws.com/images/production/2018-12-08_16-35-18_New%20Doc%202018-12-08%2022.04.14_1.jpg)
If A ( cos alpha , sin alpha) B(sin alpha , - cos alpha ) C(1,2) are the vertices of a triangle ABC then as alpha varies, the locus of its centroid is
![If a = [(Cos Alpha, Sin Alpha), (-sin Alpha, Cos Alpha)] Then Verify That A'A = I - Mathematics | Shaalaa.com If a = [(Cos Alpha, Sin Alpha), (-sin Alpha, Cos Alpha)] Then Verify That A'A = I - Mathematics | Shaalaa.com](https://www.shaalaa.com/images/_4:c824d6fd2090415e8026edbb0c866a20.png)
If a = [(Cos Alpha, Sin Alpha), (-sin Alpha, Cos Alpha)] Then Verify That A'A = I - Mathematics | Shaalaa.com
![If sin \alpha= 3/5, \sin \beta= 5/13, \alpha is in quadrant I and \beta is in quadrant II, find \sin(\alpha +\beta). | Study.com If sin \alpha= 3/5, \sin \beta= 5/13, \alpha is in quadrant I and \beta is in quadrant II, find \sin(\alpha +\beta). | Study.com](https://study.com/cimages/multimages/16/hypotenuse2272442476950271681.png)